Mid Term Question
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Is it true or wrong to say that, a ball will land at the same time if you drop it straight down from the top of a tower or if you throw it out horizontally? Either yes or no explain it with a solid reason.
No, it is not true. The ball thrown out horizontally and the one dropped straight down from the top of the tower will not land at the same time. The ball thrown out horizontally will travel a longer distance before hitting the ground compared to the ball dropped straight down.
When the ball is thrown out horizontally, it has two components of motion: horizontal and vertical. The horizontal component of the motion will keep the ball moving forward, while the vertical component of the motion will make the ball fall towards the ground. However, the ball's horizontal motion will not affect the time it takes for the ball to hit the ground.
On the other hand, when the ball is dropped straight down, it only has one component of motion, which is vertical. The ball will fall straight down towards the ground, and gravity will act upon it with the same acceleration until it hits the ground.
Therefore, even though both balls are dropped from the same height, the ball thrown out horizontally will travel a longer distance before hitting the ground, and it will take a longer time to hit the ground compared to the ball dropped straight down.
Calculate the X & Y component of car‘s average velocity, by using the data given in the following figure.
To calculate the X and Y components of the car's average velocity, we need to use the formula:
Average Velocity (v) = displacement (Δx or Δy) / time taken (t)
Here, we have two values for displacement - Δx = 5.0m and Δy = 4.0m, and the time taken is t = 3.0s.
To find the X component of the car's average velocity, we need to divide the displacement in the X direction (Δx) by the time taken (t):
X component of average velocity (vx) = Δx / t
= 5.0m / 3.0s
= 1.67 m/s (approx.)
Therefore, the X component of the car's average velocity is approximately 1.67 m/s.
To find the Y component of the car's average velocity, we need to divide the displacement in the Y direction (Δy) by the time taken (t):
Y component of average velocity (vy) = Δy / t
= 4.0m / 3.0s
= 1.33 m/s (approx.)
Therefore, the Y component of the car's average velocity is approximately 1.33 m/s.
Hence, the car's average velocity has an X component of 1.67 m/s and a Y component of 1.33 m/s.
A body is moving at 30 km/h. While veering to the right, it keeps moving at the same speed. As there force involved in this case or not. Either yes or no explain it with a solid reason.
Yes, there is a force involved in this case. Whenever an object changes its direction of motion, even if it maintains a constant speed, there is a force acting on it. This is due to the fact that any change in an object's motion requires an external force to act on it, as per Newton's first law of motion.
In this scenario, the body is veering to the right, which means it is changing its direction of motion. To achieve this change in direction, a force must be acting on the body. The force causing the body to move to the right could be due to various factors such as friction, air resistance, or a steering mechanism if the object is a vehicle.
Therefore, even though the body is moving at a constant speed, there is still a force involved in changing its direction of motion.
A man is holding a suitcase as shown in the figure. Using the mentioned data in figure calculate the magnitude & direction of suitcase’s acceleration.
Based on the given data, we can use Newton's second law of motion which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).
First, we need to determine the net force acting on the suitcase. The suitcase is being held by the man, so there are two forces acting on it: the force of gravity (its weight) and the force applied by the man. The force of gravity is given by mg, where g is the acceleration due to gravity `(9.81 m/s^2)` and m is the mass of the suitcase (17 kg). Therefore, mg = 166.6 N.
The force applied by the man is given by F = 168 N.
The Net Force acting on the suitcase is the vector sum of these two forces, which we can calculate using the Pythagorean theorem:
`Fnet = sqrt(F^2 + mg^2) = sqrt(168^2 + 166.6^2) = 236.5 N`
Next, we can use Newton's second law to calculate the acceleration of the suitcase:
`a = Fnet/m = 236.5 N / 17 kg = 13.9 m/s^2`
Finally, we need to determine the direction of the acceleration. Since the force applied by the man is in the same direction as the acceleration, the acceleration is also in the same direction as the force applied by the man. Therefore, the direction of the acceleration is the same as the direction in which the man is holding the suitcase.
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