Mid Term Question
CS201 MID TERM SOLVED MCQs || PAST PAPERS || GROUP-1 || INTRODUCTION TO PROGRAMMING || VuTech Visit Website For More Solutions www.vutechofficial.blogspot.com …
Explain the motion of an object in the following Situations with suitable examples from daily life,
a)
Speed is constant but velocity is
varying
b)
Acceleration of a body is constant but velocity is zero
c)
Speed is constant but acceleration is not zero
d) Force is applied but acceleration is zero
In this situation, the object is moving at a constant speed, but its
direction is changing. This can be seen in the motion of a car turning a
corner. The car's speed may be constant, but its velocity is changing because
its direction is changing.
In this situation, the object is not moving, but it is accelerating. This
can be seen in the motion of a car that is stopped at a red light. The car's
velocity is zero, but it is accelerating because the force of the engine is
still acting on it.
In this situation, the object is moving at a constant speed, but it is
accelerating. This can be seen in the motion of a car that is moving in a
straight line at a constant speed. The car's speed is constant, but it is
accelerating because the force of the engine is still acting on it.
In this situation, a force is applied to an object, but the object does not accelerate. This can be seen in the motion of a car that is stuck in mud. The force of the engine is still acting on the car, but the car does not accelerate because the mud is providing a force that is equal to the force of the engine.
The
required take off speed of a commercial aeroplane is 120 knots. If this
commercial aeroplane take 30-seconds to covers the airport runway path,
calculate the
a) Acceleration required during take off
b) Runway length of airport
[Hint: knot is nautical mile per hour or equal
to half a meter per seconds]
The
acceleration required during take off can be calculated using the following
formula:
a = tvf − vi
where:
In this case,
the final velocity is 120 knots, the initial velocity is 0 knots, and the time
is 30 seconds. Substituting these values into the formula, we get:
a = 30 seconds120 knots−0 knots
a = 4 knots/second
Converting
knots to meters per second, we get:
a = 4 knots/second × 1 knot/second 0.51444 meters/second
a = 2.05776 meters/second2
Therefore,
the acceleration required during take off is 2.05776 meters per second squared.
The runway
length of the airport can be calculated using the following formula:
d = 2avf2 − vi2
where:
In this case,
the final velocity is 120 knots, the initial velocity is 0 knots, and the
acceleration is 2.05776 meters per second squared. Substituting these values
into the formula, we get:
d = 2 × 2.05776 meters/second2(120 knots)2−(0 knots)2
d = 3600 meters
Therefore, the runway length of the airport is 3600 meters.
About VuTech
Soratemplates is a blogger resources site is a provider of high quality blogger template with premium looking layout and robust design. The main mission of soratemplates is to provide the best quality blogger templates which are professionally designed and perfectlly seo optimized to deliver best result for your blog.
We provide Virtual University of Pakistan Study Materials such as Solution of Assignments, GDBs, Mid Term Solved Papers, Final Term Solved Papers, Mid Term Solved MCQs, and Final Term Solved MCQs. We also provide regular Semester Quizzes, Updated Handouts, and Short Questions and Answers. We help you with your research and many other educational-related topics, as far as we know. Furthermore, Share your problem with us and Please feel free to ask any related questions.
