CS501 ASSIGNMENT 1 SOLUTION 2021 | CS501 ASSIGNMENT 1 FALL 2021 | CS501 ASSIGNMENT 1 2021 | ADVANCE COMPUTER ARCHITECTURE | VuTech

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Question No. 1

a) Write the instructions for the 0-address machine to evaluate the following expression.

    z = x² + y² + 2xy

 

Note: x, y and z represent memory locations.

 

Solution:

0-address instructions

 

PUSH x

PUSH x

MUL

PUSH y

PUSH y

MUL

ADD

PUSH x

PUSH y

MUL

PUSH 2

MUL

ADD

POP z

 

b) Calculate the execution time for 0-address machine using the above given expression by considering the following parameters:

Average CPI	Processor Frequency (f)
6	2 GHz

 

Solution:

                        Execution Time = IC x CPI x T

Where,

            IC = Instruction Count

            CPI = Average number of system clock periods to execute an instruction

            T = Clock Period

 

Put all value

ET = 14 x 6 x 2

ET = 168

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Question No. 2

Reverse assemble the following SRC machine language instructions:

B2064000h

 

Solution:

B2064000h

We convert the Hexadecimal into Binary, i.e

           

            1011    0010    0000    0110    0100    000      0000    0000   

 

First 5 bits of the binary pattern represent the opcode 22. This opcode 22 belongs to or instruction which is a D instruction of SRC. The format of modified D instruction is

 

31                    27  26                   22     21                   17  16                      12  11                     0

Op-code

Ra

rb

rc

unused

 

In D instruction, the first 5 bits represent opcode, and next 15 bits represent the one destination and two source operands of 5-bit each. We split the given bit pattern according to the type-D instruction format as

 

Next, we specify the instruction field for each the section as following:

10110	01000	00011	00100	00000
or	R8	R3	R4	unused

 

Hence, the SRC instruction will be R8, R3, R4.

1A0C0022h

 

Solution:

1A0C0022h

We convert the hexadecimal into binary pattern, i.e

 

            0001    1010    0000    1100    0000    0000    0010    0010

 

The first 5 bits of the binary pattern represent the opcode 3. This opcode 3 belongs to st instruction which is a C instruction of SRC. The format of C instruction is:

 

31                            27   26                             22  21                            17  16                              0

Op-code

ra

rb

C2

 

Next, we specify the instruction field for each the section as following:

00011	01000	00110	00000000000100010
st	R8	R3	34

 

Hence, the SRC instruction will be:- st R8,34 (R6)

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