CS401P ASSIGNMENT NO. 2 SPRING 2023 || 100% RIGHT SOLUTION || ASSEMBLY LANGUAGE PROGRAMMING || BY VuTech
Visit Website For More Solutions
www.vutechofficial.blogspot.com
KINDLY, DON’T COPY PASTE
QUESTION NO. 1
Write an assembly language program which will first take VU ID as input and then set background and foreground color of each character differently.
- Before printing the screen must be cleared.
- First VU ID will be taken as input from user.
- Then print VU ID on the screen with different foreground and background color for each character.
- For example if VU ID is bc12345678 then the ID will be printed as follows:
bc12345678
Solution:
section .data
vu_id_msg db 'Enter VU ID:', 0
vu_id_prompt db 'VU ID: ', 0
vu_id_buffer times 12 db 0 ; Buffer to store the VU ID
vu_id_length equ 12 ; Length of the VU ID
bg_colors db 0Ah, 01h, 02h, 03h, 04h, 05h, 06h, 07h, 08h, 09h ; Array of background color codes
fg_colors db 01h, 02h, 03h, 04h, 05h, 06h, 07h, 08h, 09h, 0Ah ; Array of foreground color codes
section .text
global _start
_start:
; Clear the screen
mov ah, 0h ; Function 0h - Clear screen
int 10h ; Call BIOS video services
; Display "Enter VU ID:" message
mov ah, 09h ; Function 09h - Print string
mov dx, vu_id_msg
int 21h ; Call DOS interrupt
; Read VU ID from user
mov ah, 0Ah ; Function 0Ah - Read string
mov dx, vu_id_buffer
mov cx, vu_id_length
int 21h ; Call DOS interrupt
; Display "VU ID: " prompt
mov ah, 09h ; Function 09h - Print string
mov dx, vu_id_prompt
int 21h ; Call DOS interrupt
; Set up registers for looping through the VU ID
mov esi, vu_id_buffer ; Source index points to the VU ID buffer
mov ecx, vu_id_length ; Counter for the number of characters in VU ID
; Loop through each character of VU ID and set colors
vu_id_loop:
lodsb ; Load the next character from the VU ID buffer
mov ah, 09h ; Function 09h - Print character with attribute
mov al, byte[esi-1] ; Load the character itself
mov bh, byte[bg_colors+ecx-1] ; Background color
mov bl, byte[fg_colors+ecx-1] ; Foreground color
int 10h ; Call BIOS video services
loop vu_id_loop ; Continue looping until all characters are processed
; Exit the program
mov ah, 4Ch ; Function 4Ch - Program termination
mov al, 00h ; Return code 0
int 21h ; Call DOS interrupt