CS601 ASSIGNMENT NO. 1 SPRING 2023 || 100% RIGHT SOLUTION || DATA COMMUNICATIONS || BY VuTech
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QUESTION NO. 1
(a) What is the transmission time of a packet sent by a station if the length of the packet is 1 MB and the bandwidth of the channel is 200 Kbps?
Ans:
The transmission time of a packet sent by a station depends on the size of the packet and the bandwidth of the channel. In this case, the packet size is 1 MB and the bandwidth of the channel is 200 Kbps.
To calculate the transmission time, we can use the following formula:
Transmission Time = Packet Size / Bandwidth
Substituting the values, we get:
Transmission Time = 1 MB / 200 Kbps
1 MB is equal to 1024 * 1024 bytes, and 1 byte is equal to 8 bits. Therefore, 1 MB is equal to 8 * 1024 * 1024 bits.
Substituting this value and the bandwidth in the formula, we get:
Transmission Time = (8 * 1024 * 1024 bits) / (200 Kbps)
Simplifying this expression, we get:
Transmission Time = 341.33 seconds
Therefore, the transmission time of the packet is approximately 341.33 seconds (or about 5.69 minutes) if the packet size is 1 MB and the bandwidth of the channel is 200 Kbps.
(b) There is a file of size 2 MB. How long does it take to download this file using a 1-Mbps channel?
Ans:
It would take approximately 16
seconds to download a 2 MB file using a 1-Mbps channel.
To solve this mathematically, we can use the formula:
time = size / speed
where "size" is the file size in megabytes (MB) and "speed" is the download speed in megabits per second (Mbps).
Given that the file size is 2 MB and the download speed is 1 Mbps, we can substitute these values into the formula:
time = 2 MB / 1 Mbps
To simplify this calculation, we need to convert the units so that they are both in the same format. We can convert 2 MB to megabits (Mb) by multiplying by 8, since there are 8 bits in a byte:
2 MB * 8 = 16 Mb
Now we can substitute this value into the formula:
time = 16 Mb / 1 Mbps
Simplifying further, we can cancel out the "Mb" unit in the numerator and denominator, leaving us with:
time = 16 / 1 seconds
Therefore, the time it takes to download the 2 MB file using a 1-Mbps channel is 16 seconds.
(c) If the bandwidth of the channel is 5 Kbps, how long does it take to send a frame of 100,000 bits out of this device?
Ans:
If the channel has a bandwidth of 5 Kbps, it can transmit 5,000 bits per second. To determine how long it will take to send a frame of 100,000 bits, you need to divide the total number of bits by the available bandwidth:
time = (number of bits) / (bandwidth)
time = 100,000 bits / 5,000 bits per second
time = 20 seconds
Therefore, it will take 20 seconds to send a frame of 100,000 bits through the channel with a bandwidth of 5 Kbps.
QUESTION NO. 2
Identify
the proper type of transmission mode for each of the following devices.
|
Device |
Transmission Mode |
|
FM
Radio |
Broadcast |
|
Telephone
conversations |
Point-to-Point |
|
Video
Conferencing |
Point-to-Point |
|
TV
broadcast |
Broadcast |
|
Walkie-Talkie |
Point-to-Point |