CS601 ASSIGNMENT NO. 1 SPRING 2023 || 100% RIGHT SOLUTION || DATA COMMUNICATIONS || BY VuTech

KINDLY, DON’T COPY PASTE

SUBSCRIBE, SHARE, LIKE AND COMMENTS FOR MORE UPDATES

QUESTION NO. 1

(a) What is the transmission time of a packet sent by a station if the length of the packet is 1 MB and the bandwidth of the channel is 200 Kbps?

Ans:

The transmission time of a packet sent by a station depends on the size of the packet and the bandwidth of the channel. In this case, the packet size is 1 MB and the bandwidth of the channel is 200 Kbps.

To calculate the transmission time, we can use the following formula:

Transmission Time = Packet Size / Bandwidth

Substituting the values, we get:

Transmission Time = 1 MB / 200 Kbps

1 MB is equal to 1024 * 1024 bytes, and 1 byte is equal to 8 bits. Therefore, 1 MB is equal to 8 * 1024 * 1024 bits.

Substituting this value and the bandwidth in the formula, we get:

Transmission Time = (8 * 1024 * 1024 bits) / (200 Kbps)

Simplifying this expression, we get:

Transmission Time = 341.33 seconds

Therefore, the transmission time of the packet is approximately 341.33 seconds (or about 5.69 minutes) if the packet size is 1 MB and the bandwidth of the channel is 200 Kbps.

(b) There is a file of size 2 MB. How long does it take to download this file using a 1-Mbps channel?

Ans:

It would take approximately 16 seconds to download a 2 MB file using a 1-Mbps channel.

To solve this mathematically, we can use the formula:

time = size / speed

where "size" is the file size in megabytes (MB) and "speed" is the download speed in megabits per second (Mbps).

Given that the file size is 2 MB and the download speed is 1 Mbps, we can substitute these values into the formula:

time = 2 MB / 1 Mbps

To simplify this calculation, we need to convert the units so that they are both in the same format. We can convert 2 MB to megabits (Mb) by multiplying by 8, since there are 8 bits in a byte:

2 MB * 8 = 16 Mb

Now we can substitute this value into the formula:

time = 16 Mb / 1 Mbps

Simplifying further, we can cancel out the "Mb" unit in the numerator and denominator, leaving us with:

time = 16 / 1 seconds

Therefore, the time it takes to download the 2 MB file using a 1-Mbps channel is 16 seconds.

(c) If the bandwidth of the channel is 5 Kbps, how long does it take to send a frame of 100,000 bits out of this device?

Ans:

If the channel has a bandwidth of 5 Kbps, it can transmit 5,000 bits per second. To determine how long it will take to send a frame of 100,000 bits, you need to divide the total number of bits by the available bandwidth:

time = (number of bits) / (bandwidth)

time = 100,000 bits / 5,000 bits per second

time = 20 seconds

Therefore, it will take 20 seconds to send a frame of 100,000 bits through the channel with a bandwidth of 5 Kbps.

QUESTION NO. 2

Identify the proper type of transmission mode for each of the following devices.

Device	Transmission Mode
FM Radio	Broadcast
Telephone conversations	Point-to-Point
Video Conferencing	Point-to-Point
TV broadcast	Broadcast
Walkie-Talkie	Point-to-Point

KINDLY, DON’T COPY PASTE
SUBSCRIBE, SHARE, LIKE AND COMMENTS FOR MORE UPDATES
SEND WHATSAPP OR E-MAIL FOR ANY QUERY
0325-6644800
kamranhameedvu@gmail.com
Visit Website For More Solutions
www.vutechofficial.blogspot.com